
Learn core concepts, essential formulas, and attempt practice questions designed on the latest TCS NQT testing patterns.
A father is 3 times as old as his son. 5 years ago, he was 4 times as old. Find the father's current age.
Correct Answer: A) 45
Step-by-step Solution: Let son's age be s, father's be f. f = 3s. 5 years ago: (f - 5) = 4(s - 5) => 3s - 5 = 4s - 20 => s = 15. Father's age = 3 * 15 = 45.
The sum of ages of A and B is 50. 5 years hence, their ratio is 3:2. Find B's present age.
Correct Answer: A) 19
Step-by-step Solution: Let present ages be A and B. A + B = 50. 5 years hence, sum is 50 + 10 = 60. Ratio A:B is 3:2. A's future age = 3/5 * 60 = 36. B's future age = 2/5 * 60 = 24. Present age B = 24 - 5 = 19.
Formulate present ages as variable 'x' and build the equations relative to this value.